SOLUTION: The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term? Fr solving this question, I feel that there's a problem with the question. D

Algebra ->  Sequences-and-series -> SOLUTION: The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term? Fr solving this question, I feel that there's a problem with the question. D      Log On


   

Question 1157939: The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term?





Fr solving this question, I feel that there's a problem with the question. Do you agree pls.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term?
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system%28T%5B2%5D=3%2F2%2Cand%2CT%5B5%5D=1%2F12%29


common ratio unknown but can be found. Then T%5B2%5Dr%5E3=T%5B5%5D. Maybe you can find this r, and do the rest.

Do the substitutions and then the algebra steps, and you may find r=root%283%2C12%29%2F6.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term?
Fr solving this question, I feel that there's a problem with the question. Do you agree pls.
There probably is because the first term, or .

Did you copy it correctly?