SOLUTION: A particular fruit's weights are normally distributed, with a mean of 706 grams and a standard deviation of 22 grams.
If you pick one fruit at random, what is the probability th
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-> SOLUTION: A particular fruit's weights are normally distributed, with a mean of 706 grams and a standard deviation of 22 grams.
If you pick one fruit at random, what is the probability th
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Question 1157449: A particular fruit's weights are normally distributed, with a mean of 706 grams and a standard deviation of 22 grams.
If you pick one fruit at random, what is the probability that it will weigh between 757 grams and 763 grams Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
=(757-706)/22=2.32
=(763-706)/22=2.59
the probability of z being between those two values is 0.0054
