SOLUTION: A man wishes to give his 12 books to his 3 children, so that the first shall receive 5, the second 4, and the third 3. In how many ways can he give the books?

Algebra ->  Probability-and-statistics -> SOLUTION: A man wishes to give his 12 books to his 3 children, so that the first shall receive 5, the second 4, and the third 3. In how many ways can he give the books?      Log On


   



Question 1157327: A man wishes to give his 12 books to his 3 children, so that the first shall receive 5, the second 4, and the third 3. In how many ways can he give the books?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


The rules are not clear; so I will assume the easy solution.

The number of ways he can give the books is the number of ways to arrange the numbers 3, 4, and 5 in a row: 3!=6 ways.
   1st   2nd   3rd
  child child child
 -------------------
    3     4     5
    3     5     4
    4     3     5
    4     5     3
    5     3     4
    5     4     3



Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
.

He can select 5 books for the first child by C%5B12%5D%5E5 ways = %2812%2A11%2A10%2A9%2A8%29%2F%281%2A2%2A3%2A4%2A5%29 = 792 ways.  (the order is not important).


He then can select 4 books from remaining  12-5 = 7 books for the second child by C%5B12-5%5D%5E4 = C%5B7%5D%5E4 ways = %287%2A6%2A5%2A4%29%2F%281%2A2%2A3%2A4%29 = 35 ways.  


The rest of the books go to the third child, with no choice.



In all, there are  792*35 = 27720 different ways.    ANSWER

Solved.

------------------

On Combinations,  see introductory lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.