SOLUTION: Find the inverse of the function (a) f(x)= x^2+2x-1, x>0

Algebra ->  Inverses -> SOLUTION: Find the inverse of the function (a) f(x)= x^2+2x-1, x>0      Log On


   



Question 1157185: Find the inverse of the function
(a) f(x)= x^2+2x-1, x>0

Found 3 solutions by josgarithmetic, MathLover1, Edwin McCravy:
Answer by josgarithmetic(39625) About Me  (Show Source):
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=+x%5E2%2B2x-1, x%3E0
the inverse of the function:
f%28x%29=+y
y=+x%5E2%2B2x-1..swap variables
x=+y%5E2%2B2y-1.......solve for y
x%2B1=+y%5E2%2B2y.......complete square
x%2B1=+%28y%5E2%2B2y%2B1%5E2%29-1%5E1
x%2B1=+%28y%2B1%29%5E2-1
x%2B1%2B1=+%28y%2B1%29%5E2
%28y%2B1%29%5E2=x%2B2
y%2B1=sqrt%28x%2B2%29
y=%28-1%2B-sqrt%28x%2B2%29%29
solution: if x%3E0, f'%28x%29=sqrt%28x%2B2%29-1


Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
The above two solutions are incorrect.

Find the inverse of the function
f(x)= x^2+2x-1, x>0
That's this parabola with the dotted part discarded.
We want to find its inverse:



So f(x) is this graph:



We want to find the equation of its inverse, the blue graph below, 
which is the projection of f(x) across the "identity line", which is 
the green dotted line below through the origin that leans right at 
am angle of 45°, and that has equation y=x.



To find the equation for the graph of the blue curve,

%22f%28x%29%22=+x%5E2%2B2x-1  x%3E0

Step 1. Change f(x) to y

y=+x%5E2%2B2x-1   x%3E0

Step 2. Interchange x and y

x=+y%5E2%2B2y-1   y%3E0

Step 3. Solve for y

Swap sides:
y%5E2%2B2y-1=x   y%3E0
y%5E2%2B2y-1-x=0
Use quadratic formula with a=1, b=2, c=-1-x
y+=+%28-%282%29+%2B-+sqrt%28%282%29%5E2-4%281%29%28-1-x%29%29%29%2F%282%281%29%29+
y+=+%28-2+%2B-+sqrt%284-4%28-1-x%29%29%29%2F2+
y+=+%28-2+%2B-+sqrt%284%2B4%2B4x%29%29%2F2+
y+=+%28-2+%2B-+sqrt%288%2B4x%29%29%2F2+
y+=+%28-2+%2B-+sqrt%284%282%2Bx%29%29+%29%2F2+
y+=+%28-2+%2B-+2sqrt%282%2Bx%29+%29%2F2+
y+=+%282%28-1+%2B-+sqrt%282%2Bx%29+%29%29%2F2+
y+=+%28cross%282%29%28-1+%2B-+sqrt%282%2Bx%29+%29%29%2Fcross%282%29+
y+=+-1+%2B-+sqrt%282%2Bx%29  y%3E0

We must require that y > 0, and therefore

-1+%2B-+sqrt%282%2Bx%29+%3E+0
%22%22+%2B-+sqrt%282%2Bx%29+%3E+1
This tells us that we can only use the + sign:
sqrt%282%2Bx%29+%3E+1
Square both sides:
2%2Bx+%3E+1
x%3E-1 

So equation of the blue curve is

y+=+-1%2Bsqrt%282%2Bx%29     x%3E-1

Step 4.  Finally, change y to f-1(x)

f%5E%28-1%29%28x%29+=+-1%2Bsqrt%282%2Bx%29   x%3E-1

Edwin