SOLUTION: A ball is thrown vertically upward from the ground with an initial velocity of 103 feet per second. What will be the ball's maximum height?

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Question 1157133: A ball is thrown vertically upward from the ground with an initial velocity of 103 feet per second. What will be the ball's maximum height?
Answer by ikleyn(52765) About Me  (Show Source):
You can put this solution on YOUR website!
.

You write the equation for the height

    h(t) = -16*t^2 + 103t.     (1)


From the general theory of the maximum of quadratic function you find the time for reaching the maximum

    t = %28-103%29%2F%282%2A%28-16%29%29 = 3.218 seconds.


Then you substitute this value  t= 3.218 seconds for time into equation (1), and you get

    h%5Bmaximum%5D = -16*3.218^2 + 103*3.218 = 165.77 feet.    ANSWER

Solved.

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In this site,  there is a bunch of lessons on a projectile thrown/shot/launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Consider these lessons as your textbook,  handbook,  tutorials and  (free of charge)  home teacher.
Read them attentively and learn how to solve this type of problems once and for all.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.