SOLUTION: A ball is thrown vertically upward from the ground with an initial velocity of 103 feet per second. When will the ball reach its maximum height?

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Question 1157130: A ball is thrown vertically upward from the ground with an initial velocity of 103 feet per second. When will the ball reach its maximum height?
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.

Looking from the Physics point of view, you simply write

    t = u%2Fg,

where g is the gravity acceleration (in ft/s^2), u is an initial velocity and t is the time to reach maximum height.


Substituting the data, you momentarily get  

    t = 103%2F32 = 3.218 seconds.



Looking from the School Math/Algebra point of view, you write the equation for the height

    h(t) = -16*t^2 + 103*t,

and from the general theory for the maximum value (vertex) of a parabola you get

    t = 103%2F%282%2A16%29 = 3.218 seconds, i.e. the same answer.

Solved.

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On finding the maximum/minimum of a quadratic function see the lessons
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.