SOLUTION: use synthetic division or other methods to find the value of k that makes the linear expression a factor of the given expression.
x^2-kx+4;x+2
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-> SOLUTION: use synthetic division or other methods to find the value of k that makes the linear expression a factor of the given expression.
x^2-kx+4;x+2
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Question 1157080: use synthetic division or other methods to find the value of k that makes the linear expression a factor of the given expression.
x^2-kx+4;x+2 Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39630) (Show Source):
The other method is to apply the Remainder theorem.
The remainder theorem says that the binomial (x+2) divide a polynomial if and only id the (-2) is the root of the polynomial.
So, you replace x in the given polynomial by -2 and write
(-2)^2 - k*(-2) + 4 = 0,
or, which is the same
4 + 2k + 4 = 0,
2k = -8,
k = -8/2 = -4,
and it is your ANSWER
Solved.
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Theorem (the remainder theorem)
1. The remainder of division the polynomial by the binomial is equal to the value of the polynomial.
2. The binomial divides the polynomial if and only if the value of is the root of the polynomial , i.e. .
3. The binomial factors the polynomial if and only if the value of is the root of the polynomial , i.e. .