SOLUTION: {{{((1+i)/(1-i))^2 + 1/(x+iy) = 1+i}}}

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Question 1157072: %28%281%2Bi%29%2F%281-i%29%29%5E2+%2B+1%2F%28x%2Biy%29+=+1%2Bi
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
%28%281+%2B+i%29%2F%281+-+i%29%29%5E2+%2B+1%2F%28x+%2B+iy%29+=+1+%2B+i 

We simplify what's squared in the the first term



Now we square it to get the complete first term simplified:

matrix%281%2C2%2Cfirst%2Cterm%29=%28%281+%2B+i%29%2F%281+-+i%29%29%5E2=i%5E2=-1

Substituting -1 for the first term

-1+%2B+1%2F%28x+%2B+iy%29+=+1+%2B+i

Add 1 to both sides:

1%2F%28x+%2B+iy%29+=+2+%2B+i

Multiply both sides by (x + iy)

1+=+%28x%2Biy%29%282+%2B+i%29

FOIL out the right side:

1+=+2x%2Bix%2B2iy+%2B+i%5E2y

1+=+2x%2Bix%2B2iy%2B%28-1%29y

1+=+2x%2Bix%2B2iy-y

Set the real terms on the left equal to the real terms on the right:

1=2x-y

Set the imaginary terms on the left equal to the imaginary terms on
the right (there aren't any on the left so we use 0):

0=ix%2B2iy

divide through by i

0=x%2B2y

Solve the system:

system%281=2x-y%2C0=x%2B2y%29

Solve the first equation for y

y=2x-1

Substitute in the 2nd equation of the system:

0=x%2B2%282x-1%29

Distribute:

0=x%2B4x-2

Combine terma:

0=5x-2

Add 2 to both sides:

2=5x

Divide both sides by 5

2%2F5=x

Substitute for x in

y=2x-1

y=2%282%2F5%29-1

y=4%2F5-1

Multiple through by 5

5y=4-5

5y=-1

Divide both sides by 5

y=-1%2F5 



Edwin