SOLUTION: Find the equation of the line that is equidistant from the points (-3, -6) and (4, 7) USING THE LOCUS DEFINITION METHOD. Write the equation in slope intercept form. Please show st

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Find the equation of the line that is equidistant from the points (-3, -6) and (4, 7) USING THE LOCUS DEFINITION METHOD. Write the equation in slope intercept form. Please show st      Log On


   

Question 1156998: Find the equation of the line that is equidistant from the points (-3, -6) and (4, 7) USING THE LOCUS DEFINITION METHOD. Write the equation in slope intercept form.
Please show steps and solve all the way thank you!!
Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
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equation of the line that is equidistant from the points (-3, -6) and (4, 7)
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%28x%2B3%29%5E2%2B%28y%2B6%29%5E2=%28x-4%29%5E2%2B%28y-7%29%5E2

x%5E2%2B6x%2B9%2By%5E2%2B12y%2B36=x%5E2-8x%2B16%2By%5E2-14y%2B49

6x%2B12y%2B45=-8x-14y%2B65

14x%2B26y=20

7x%2B13y=10-----------solve for y in terms of x if you want