SOLUTION: Find the number of ordered triples (x,y,z) of real numbers that satisfy {{{x + y - z = 0}}}, {{{xz - xy + yz = 27}}}, {{{xyz = 54}}}.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the number of ordered triples (x,y,z) of real numbers that satisfy {{{x + y - z = 0}}}, {{{xz - xy + yz = 27}}}, {{{xyz = 54}}}.      Log On


   



Question 1156959: Find the number of ordered triples (x,y,z) of real numbers that satisfy
x+%2B+y+-+z+=+0,
xz+-+xy+%2B+yz+=+27,
xyz+=+54.

Answer by my_user_id(3) About Me  (Show Source):
You can put this solution on YOUR website!
Because xyz equals 54, you have to find 3 factors that multiply to 54 while x-y=z. In this problem, the only solution that would word is x=3, y=3, and z=6.