SOLUTION: A car traveled 1650 miles at a certain speed. If the speed had been 11 MPH faster, the trip could have been made in 5 hours less time. Find the speed.

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Question 1156854: A car traveled 1650 miles at a certain speed. If the speed had been 11 MPH faster, the trip could have been made in 5 hours less time. Find the speed.
Found 3 solutions by josgarithmetic, josmiceli, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
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1650 miles at a certain speed. If the speed had been 11 MPH faster, the trip could have been made in 5 hours less time.
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              SPEED          TIME        DISTANCE

DONE             r           1650/r         1650

IF              r+11         1650/(r+11)    1650

DIFFERENCE                      5

1650%2Fr-1650%2F%28r%2B11%29=5
.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the actual speed
+s+%2B+11+ = the faster speed
Let +t+ = actual traveling time in hrs
+t+-+5+ = time for the faster speed
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Equation for the actual speed:
(1) +1650+=+s%2At+
Equation for the faster speed:
(2) +1650+=+%28+s+%2B+11+%29%2A%28+t+-+5+%29+
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(1) +t+=+1650+%2F+s+
Plug this into (2)
(2) +1650+=+%28+s+%2B+11+%29%2A%28+1650%2Fs+-+5+%29+
(2) +1650+=+1650+%2B+18150%2Fs++-+5s+-+55+
(2) +18150%2Fs+-+5s+=+55+
(2) +18150+-+5s%5E2+=+55s+
(2) +5s%5E2+%2B+55s+-+18150+=+0+
(2) +s%5E2+%2B+11s+-+3630+=+0+
I'll complete the square:
(2) +s%5E2+%2B+11s+%2B+%28+11%2F2+%29%5E2+=+3630+%2B+%28+11%2F2+%29%5E2+
(2) +%28+s+%2B+11%2F2+%29%5E2+=+14520%2F4++%2B+121%2F4+
(2) +%28+s+%2B+11%2F2+%29%5E2+=+14641+%2F+4+
(2) +%28+s+%2B+11%2F2+%29%5E2+=%28++121%2F2+%29%5E2+
(2) +s+%2B+11%2F2+=+121%2F2+
(2) +s+=+110%2F2+
(2) +s+=+55+
The actual speed was 55 mi/hr
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check:
(1) +1650+=+s%2At+
(1) +1650+=+55%2At+
(1) +t+=+30+ hrs
and
(2) +1650+=+%28+s+%2B+11+%29%2A%28+t+-+5+%29+
(2) +1650+=+%28+55+%2B+11+%29%2A%28+t+-+5+%29+
(2) +1650+=+66t+-+330+
(2) +66t+=+1980+
(2) +t+=+30+ hrs
OK
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check my math

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

A car traveled 1650 miles at a certain speed. If the speed had been 11 MPH faster, the trip could have been made in 5 hours less time. Find the speed.
Let speed be S
Then we get the following TIME equation: matrix%281%2C3%2C+%221%2C650%22%2FS%2C+%22=%22%2C+%221%2C650%22%2F%28S+%2B+11%29+%2B+5%29
matrix%281%2C3%2C+330%2FS%2C+%22=%22%2C+330%2F%28S+%2B+11%29+%2B+1%29 ----- Factoring out GCF, 5, in numerator
330(S + 11) = 330S + S(S + 11) ------ Multiplying by LCD, S(S + 11)
matrix%281%2C3%2C+330S+%2B+%223%2C630%22%2C+%22=%22%2C+330S+%2B+S%5E2+%2B+11S%29
matrix%281%2C3%2C+S%5E2+%2B+11S+-+%223%2C630%22%2C+%22=%22%2C+0%29
(S - 55)(S + 66) = 0
Speed or highlight_green%28matrix%281%2C4%2C+S%2C+%22=%22%2C+55%2C+mph%29%29 OR S = - 66 (ignore)