SOLUTION: Two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord.

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Question 1156825: Two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord.
Answer by ikleyn(52814) About Me  (Show Source):
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Notice that this chord BISECTS the segment, connecting the centers (it is clear from symmetry).


Thus the right angled triangle arises with the hypotenuse of 10 (the radius) and the leg of 12/2 = 6 cm long.


Hence, half of the chotd has the length of  sqrt%2810%5E2+-+6%5E2%29 = 8 cm.


It means that the entire chord is 8 + 8 = 16 cm long.    ANSWER

Solved.