SOLUTION: solve the system by addition 3x - y =1 3x -y = 2

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Question 115665: solve the system by addition
3x - y =1
3x -y = 2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

3%2Ax-1%2Ay=1
3%2Ax-1%2Ay=2

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 3 to some equal number, we could try to get them to the LCM.

Since the LCM of 3 and 3 is 3, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -1 like this:

1%2A%283%2Ax-1%2Ay%29=%281%29%2A1 Multiply the top equation (both sides) by 1
-1%2A%283%2Ax-1%2Ay%29=%282%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
3%2Ax-1%2Ay=1
-3%2Ax%2B1%2Ay=-2

Notice how 3 and -3 and 1 and 1 add to zero (ie 3%2B-3=0 -1%2B1=0)

However 1 and -2 add to -1 (ie 1%2B-2=-1);


So we're left with

0=-1


which means no value of x or y value will satisfy the system of equations. So there are no solutions


So this system is inconsistent