SOLUTION: If P(A)=62.9%, P(B)=45.2%, and P(A and B)=21%, what is the probability of A or B?

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Question 1156606: If P(A)=62.9%, P(B)=45.2%, and P(A and B)=21%, what is the probability of A or B?
Answer by Boreal(15235) About Me  (Show Source):
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P(A or B)=P(A)+P(B)-P(A and B)
=0.629+0.452-0.21
=1.081-0.210
=0.871