SOLUTION: Class records at Rockwood College indicate that a student selected at random has probability 0.79 of passing French 101. For the student who passes French 101, the probability is 0
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-> SOLUTION: Class records at Rockwood College indicate that a student selected at random has probability 0.79 of passing French 101. For the student who passes French 101, the probability is 0
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Question 1156507: Class records at Rockwood College indicate that a student selected at random has probability 0.79 of passing French 101. For the student who passes French 101, the probability is 0.86 that he or she will pass French 102. What is the probability that a student selected at random will pass both French 101 and French 102? (Round your answer to three decimal places.)
According to the problem context, we have two events
A = (passed French 101)
B = (passed French 102),
and the set B is inside of the set A.
Therefore, P(A and B) = P(B) = 0.79*0.86. ANSWER
