SOLUTION: If two playing cards are drawn from a pack of 52 cards without replacement. Find
out the probability of getting both aces
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-> SOLUTION: If two playing cards are drawn from a pack of 52 cards without replacement. Find
out the probability of getting both aces
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Question 1156454: If two playing cards are drawn from a pack of 52 cards without replacement. Find
out the probability of getting both aces Found 2 solutions by Boreal, Edwin McCravy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! probability of the first is 4/52 or 1/13
second will be 3/51 or 1/17, since both numerator and denominator decrease by 1.
The product is the answer and is 1/221
There are 4 aces in a deck of 52. So about 4/52nds or 1/13th of the time you
will draw an ace the first time.
When you do draw an ace the first time, you will have a deck of 51 with only 3
aces. So 3/51 or 1/17th of those 1/13ths of the time when you draw an ace on
the first draw, you will also draw an ace on the second draw.
So 1/17th of those 1/13ths of the time when you drew an ace on the first draw,
you will also draw an ace on the second draw.
So 1/17th of 1/13ths of the time is (1/13)×(1/17) = 1/221sts of the time.
So the probability of drawing two aces in a row without replacement is 1/221.
So you'll have to draw two cards every morning for 221 days, to be able to
expect that 1 of those 221 days you'll draw two aces in a row.
Answer: 1/221
Edwin
