SOLUTION: n a survey of 1053 1053 ​people, 780 780 people said they voted in a recent presidential election. Voting records show that 71 71​% of eligible voters actually did vot

Algebra ->  Probability-and-statistics -> SOLUTION: n a survey of 1053 1053 ​people, 780 780 people said they voted in a recent presidential election. Voting records show that 71 71​% of eligible voters actually did vot      Log On


   

Question 1156449: n a survey of
1053
1053 ​people,
780
780 people said they voted in a recent presidential election. Voting records show that
71
71​% of eligible voters actually did vote. Given that
71
71​% of eligible voters actually did​ vote, (a) find the probability that among
1053
1053 randomly selected​ voters, at least
780
780 actually did vote.​ (b) What do the results from part​ (a) suggest?
​(a) ​P(X
greater than or equals
≥
780
780​)
equals
=
nothing
​(Round to four decimal places as​ needed.)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
the point estimate is 0.7407
one tail test with a z-value = 0.7407-0.71)/sqrt (0.71*0.29/1053)
that equals 2.195
that probability is 0.0140 rounding at end.
The results suggest that it is unlikely to get this sort of result if the true value were 71%. Therefore, the true value is likely more than 71%.