SOLUTION: Suppose a business owner has a choice of 5locations to establish her business. She decides to rank each location using 2 criteria. How many ways can she rank the 5 cities? What if

Algebra ->  Permutations -> SOLUTION: Suppose a business owner has a choice of 5locations to establish her business. She decides to rank each location using 2 criteria. How many ways can she rank the 5 cities? What if       Log On


   



Question 1156369: Suppose a business owner has a choice of 5locations to establish her business. She decides to rank each location using 2 criteria. How many ways can she rank the 5 cities? What if she wishes to rank only the top three. How many ways can she rank them?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


(1) 5*4*3*2*1 = 120

(2) 5*4*3 = 60


Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.

This problem, as it is worded, posted and presented, is partly provocation and partly nonsense.

I will explain it why.


Five locations with 2 criteria I can interpret as 5 points in a coordinate plane with coordinates x any y,
that represent that "two criteria".

This set of five points is not necessary ordered.

Therefore, it is not clear, how these points (locations) can be "ranged".

5 objects can be ordered (permuted) in 5! ways, but it is not ranging with the use of criterion/criteria.

So, the meaning of this "problem" is dark.

Therefore, in the form, in which it is presented, it is not a Math problem, at all.

It is collection of words without clear sense.