SOLUTION: Sketch the set of complex numbers that satisfy |z|=1

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Question 1156361: Sketch the set of complex numbers that satisfy |z|=1
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

For any complex number z+=+a%2Bbi, the magnitude of the complex number is abs%28z%29+=+sqrt%28a%5E2%2Bb%5E2%29. We can see this through finding the distance from (0,0) to (a,b). This is effectively the same as using the pythagorean theorem.

We want abs%28z%29+=+1, so sqrt%28a%5E2%2Bb%5E2%29+=+1 which becomes a%5E2%2Bb%5E2+=+1 when we square both sides. Note how (a,b) = (x,y), so we go from a%5E2%2Bb%5E2+=+1 to x%5E2%2By%5E2+=+1

x%5E2%2By%5E2+=+1 is a circle with radius 1 and center (0,0). Compare this to the general form %28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2.

The diagram will be an empty (or not filled in) circle because we're only considering points on the circle itself.

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