SOLUTION: Locate the critical points of the following function. Then use the second derivative test to determine whether they correspond to local maxima, local minima, or neither. f(x)=-e^

Algebra ->  Test -> SOLUTION: Locate the critical points of the following function. Then use the second derivative test to determine whether they correspond to local maxima, local minima, or neither. f(x)=-e^      Log On


   



Question 1156266: Locate the critical points of the following function. Then use the second derivative test to determine whether they correspond to local maxima, local minima, or neither.
f(x)=-e^x x-3

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
I interpreted this as (x-3)*e^x.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x-3%29%2Ae%5Ex%29%29
derivative is (x-3)(e^x)+e^x
set it equal to 0
e^(x)+(x-3+1)=0
e^x(x-2)=0
critical point at x=2
second derivative is (x-1)e^x, which is positive where x=2
it is a minimum
root is where x=3
Here is the plot for e^(x^2-3x)
graph%28300%2C300%2C-5%2C5%2C-1%2C1%2Ce%5E%28x%5E2-3x%29%29
Here x=3/2 is the minimum and y=0.1055 is the value.
f''(x)=4x^2-12x+11 (e^(x^2-3x)) which is positive when x=3/2