SOLUTION: Solve -2 sin0=1.2 in the interval from 0 to 2π

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Question 1156245: Solve -2 sin0=1.2 in the interval from 0 to 2π
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+-2%2Asin%28+theta+%29+=+1.2+
++0+%3C++theta++%3C++2pi+
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+sin%28+theta+%29+ must be negative so that
( - ) x ( - ) = ( + )
The sin function is negative in the 3rd and 4th
quadrants
+sin%28+theta+%29+=+-1.2%2F2+
+sin%28+theta+%29+=+-.6+
+theta+=+arc+sin%28+-.6+%29+
+theta+=+180+%2B+36.87+
+theta+=+216.87+
and
+theta+=+360+-+36.87+
+theta+=+323.13+
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Those are the 2 solutions for ++0+%3C++theta++%3C++2pi+