SOLUTION: A batting order must be created from the 9 starters on a baseball team. How many batting orders are possible if Jack has to go up to 4th?

Choose the most restrictive things first, which is the 4th batter.
 There is only 1 player to choose for the 4th batter (as Jack).
Then there are 8 remaining players to choose for the 1st batter.
Then there are 7 remaining players to choose for the 2nd batter. 
Then there are 6 remaining players to choose for the 3rd batter.
Then there are 5 remaining players to choose for the 5th batter.
Then there are 4 remaining players to choose for the 6th batter.
Then there are 3 remaining players to choose for the 7th batter.
Then there are 2 remaining players to choose for the 8th batter.
Then there are 1 remaining players to choose for the 9th batter

Answer 1∙8∙7∙6∙5∙4∙3∙2∙1 = 1∙8! = 8! = 40320

Edwin