SOLUTION: Mike has $1.45 in dimes and nickels. If he has 8 more nickels than dimes, how many of each coin does he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Mike has $1.45 in dimes and nickels. If he has 8 more nickels than dimes, how many of each coin does he have?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1156168: Mike has $1.45 in dimes and nickels. If he has 8 more nickels than dimes, how many of each coin does he have?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
n-d=8
n=8%2Bd
n=d%2B8


5%28d%2B8%29%2B10d=145--------------simplify and solve.
.
.