SOLUTION: Julie had saved 105 coins form her daily allowance. if the coins consists of 5-peso coins and 10-peso coins amounting to 950 pesos, how many of each kind of coin did she have?

Algebra ->  Matrices-and-determiminant -> SOLUTION: Julie had saved 105 coins form her daily allowance. if the coins consists of 5-peso coins and 10-peso coins amounting to 950 pesos, how many of each kind of coin did she have?       Log On


   

Question 1155900: Julie had saved 105 coins form her daily allowance. if the coins consists of 5-peso coins and 10-peso coins amounting to 950 pesos, how many of each kind of coin did she have?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
p of the ten-peso coins
105-p of the five-peso coins

10p%2B5%28105-p%29=950
Simplify and solve.