SOLUTION: Suppose a cylindrical storage tank is to contain V=16,000π cubic feet (about 400,000 gallons) is to be built into the ground to catch runoff water so it needs no top. Suppose, fur

Algebra ->  Surface-area -> SOLUTION: Suppose a cylindrical storage tank is to contain V=16,000π cubic feet (about 400,000 gallons) is to be built into the ground to catch runoff water so it needs no top. Suppose, fur      Log On


   



Question 1155851: Suppose a cylindrical storage tank is to contain V=16,000π cubic feet (about 400,000 gallons) is to be built into the ground to catch runoff water so it needs no top. Suppose, further, that the cost of the base of the tank is $10 per square foot and sides $8.64 per square foot. What dimensions will lead to minimal - cost tank?
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28v=16000pi=h%2Api%2Ar%5E2%2Cc=pi%2Ar%5E2%2A10%2B2pi%2Arh%2A8.64%29
with v for the volume, c for the cost.
system%28h=v%2F%28pi%2Ar%5E2%29%2Cc=10pi%2Ar%5E2%2B2%2A8.64pi%28v%2F%28pi%2Ar%29%29%29

c=10pi%2Ar%5E2%2B17.28v%2Fr

c=10pi%2Ar%5E2%2B%2817.28%29%2816000%29pi%2Fr
.
.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the diameter of the base
Let +h+ = the height of the tank
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The circumference, +C+, of the base is:
+C+=+pi%2Ad+
The area, +A%5Bb%5D+, of the base is:
+A%5Bb%5D+=+pi%2A%28d%2F2%29%5E2+
----------------------------------------
The volume, +V+ is:
+V+=+pi%2A%28+d%2F2+%29%5E2+%2A+h+
+16000%2Api+=+pi%2A%28+d%5E2%2F4+%29%2Ah+
+64000+=+d%5E2%2Ah+
+h+=+64000+%2F+d%5E2+
--------------------------------------
The area of the sides, +A%5Bs%5D+, is:
+A%5Bs%5D+=+pi%2Ad%2A%28+64000+%2F+d%5E2+%29+
+A%5Bs%5D+=+%28+64000%2Api+%29+%2F+d+
--------------------------------------
The cost, +C%5Bt%5D+, of the tank is:
+C%5Bt%5D+=+8.64%2A%28%28+64000%2Api+%29%2Fd+%29+%2B+10%2A%28+pi%2Ad%5E2+%29+%2F+4+
+C%5Bt%5D+=+1737175.07+%2F+d+%2B+7.85398%2Ad%5E2+
The slope of this curve is:
+C%5Btt%5D+=+-1737175.07+%2F+d%5E2+%2B+15.70796d+
Set slope = 0
+0+=+-1737175.07+%2F+d%5E2+%2B+15.70796d+
+1737175.07+%2F+d%5E2+=++15.70796d+
+d%5E3+=++1737175.07+%2F+15.70796+
+d+=+120.21201+%2F+2.5044167+
+d+=+48.0000003+
+d+=+48+ ft
and
+h+=+64000+%2F+d%5E2%0D%0A%7B%7B%7B+h+=+64000+%2F+2304+
+h+=+27.778+ ft
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The diameter for min cost is 48 ft
The height for min cost is 27.778 ft
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Here's the plot:

-----------------------------
The min cost is:
+C%5Bt%5D+=+1737175.07+%2F+d+%2B+7.85398%2Ad%5E2+
+C%5Bt%5D+=+1737175.07+%2F+48+%2B+7.85398%2A48%5E2+
+C%5Bt%5D+=+36191.15+%2B+18095.57+
+C%5Bt%5D+=+54286.72+
$54,286.72 looks close to min in the plot
Get a 2nd opinion if needed
and check my math