Question 1155706: Twice last month, Judy Carter rented a car from a car rental company and traveled around the Southwest on business. The company rents its car for a daily fee, plus an additional charge per mile driven. Judy recalls that her first trip lasted 4 days, she drove 450 miles, and the rental cost her $ 210.00 . On her second business trip she drove 200 miles in 3 days, and paid $ 130.00 for the rental. Find the daily fee, and find the mileage charge.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Twice last month, Judy Carter rented a car from a car rental company and traveled around the Southwest on business.
The company rents its car for a daily fee, plus an additional charge per mile driven.
Judy recalls that her first trip lasted 4 days, she drove 450 miles, and the rental cost her $ 210.00 .
On her second business trip she drove 200 miles in 3 days, and paid $ 130.00 for the rental.
Find the daily fee, and find the mileage charge.
:
let f = the daily fee
let m = cost per mile
:
Write a equation for each trip
"first trip lasted 4 days,she drove 450 miles, and the rental cost her $210.00"
4f + 450m = 210
"second business trip she drove 200 miles in 3 days, and paid $ 130.00"
3f + 200m = 130
:
use elimination, mult the 1st eq by 3, the 2nd eq by 4
12f + 1350m = 630
12f + 800m = 520
---------------------subtraction eliminates f, find m
0 + 550m = 110
m = 110/550
m = $.20 cents per mile
:
Find f using the 2nd original equation
3f + 200(.20) = 130
3f + 40 = 130
3f = 130 - 40
f = 90/3
f = $30 is the daily fee
:
:
Check these solutions in the 1st equation
4(30) + 450(.20) =
120 + 90 = 210
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