SOLUTION: Sue can do an inventory by herself in 6 hours. Sue and Ann work together on the inventory for 3 hours. Then Ann finishes up the job by herself in 2 additional hours. How many hours
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Question 1155702: Sue can do an inventory by herself in 6 hours. Sue and Ann work together on the inventory for 3 hours. Then Ann finishes up the job by herself in 2 additional hours. How many hours would it take Ann to do the entire inventory if she worked alone? Found 3 solutions by ankor@dixie-net.com, greenestamps, josgarithmetic:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Sue can do an inventory by herself in 6 hours.
Sue and Ann work together on the inventory for 3 hours.
Then Ann finishes up the job by herself in 2 additional hours.
How many hours would it take Ann to do the entire inventory if she worked alone?
:
let a = time required by Ann working alone
let the completed job = 1
"Sue and Ann work together on the inventory for 3 hours. Then Ann finishes up the job by herself in 2 additional hours."
Sue works a total of 5 hrs, Ann works 3 + = 1
Multiply equation by 6a
5a + 6(3) = 6a
18 = 6a - 5a
18 = a
Ann required 18 hrs to do the job alone
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See if that checks out + = 1 + = 1
The solution from the other tutor has Sue working 5 hours and Ann working 3; the problem says it should be the other way around.
Perhaps that tutor will see this and correct his response.
Below is my way of solving the problem, which is somewhat informal and therefore different than his.
Sue can do the whole job herself in 6 hours. So in working with Ann for 3 hours, Sue herself does half the job.
Ann works a total of 3+2=5 hours on the job. In that time she does half the job; that means the time it takes her to do the whole job alone is 10 hours.
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