SOLUTION: The weekly profit(in dollars) of a company making and selling x virtual pets each week is given by {{{ P(x)= -x^2+980x-3000 }}}. What is the maximum profit, and how many virtual pe
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-> SOLUTION: The weekly profit(in dollars) of a company making and selling x virtual pets each week is given by {{{ P(x)= -x^2+980x-3000 }}}. What is the maximum profit, and how many virtual pe
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Question 1155580: The weekly profit(in dollars) of a company making and selling x virtual pets each week is given by . What is the maximum profit, and how many virtual pets should be made and sold each week to maximize profit?
You can put this solution on YOUR website! The weekly profit(in dollars) of a company making and selling x virtual pets each week is given by P(x) = -x^2 + 980x - 3000.
What is the maximum profit, and how many virtual pets should be made and sold each week to maximize profit?
:
-x^2 + 980x - 3000 is quadratic equation, the max value is on the axis of symmetry.
Use the formula x = -b/(2a), where a=-1; b=980
x =
x = +490 items sold for max profit
:
Find the actual profit at his value
P(x) = -490^2 + 980(490) - 3000
P(x) = -240100 + 480200 - 3000
P(x) = $237,100 profit
You can put this solution on YOUR website!
The formula for the x-value of the vertex
( maximum in this case ) is:
Plug this result back into equation:
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There maximum ;profit is $237,000
and the number of virtual pets sold
is 490
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check:
Here's the plot:
Looks about right
