SOLUTION: Using 36 feet of rope, enclose a rectangle with the largest possible area. Next, enclose a rectangle with the smallest possible area. In both cases, use dimensions that are whole

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Question 1155452: Using 36 feet of rope, enclose a rectangle with the largest possible area. Next, enclose a rectangle with the
smallest possible area. In both cases, use dimensions that are whole feet.
Answer by ikleyn(52878) About Me  (Show Source):
You can put this solution on YOUR website!
.

When the perimeter is given,  a rectangle of the maximum area is the square with the side length of  1%2F4  the perimeter.

It is well known fact,  See,  for example, the lesson
    - A rectangle with a given perimeter which has the maximal area is a square
in this site.

So,  in your case, the answer to your first question is a square with the side length of  36%2F4 = 9 feet.

Regarding the second question,  a rectangle should have dimensions 1 ft by 17 ft.