Question 1155425: Determine the location and value of the absolute extreme values of f on the given interval, if they exist.
f(x)=5sin^2 x on [0,pi)
Answer by greenestamps(13203)   (Show Source):
You can put this solution on YOUR website!
The range of sin(x) on [0,pi) is [0,1], so the range of sin^2(x) is also [0,1]; then the range of 5*sin^2(x) on that interval is [0,5].
The minimum value is 0 when sin(x)=0, which is when x is 0; the maximum value is 5 when sin(x)=1, which is when x is pi/2.
ANSWERS:
minimum value at (0,0)
maximum value at (pi/2,5)
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