SOLUTION: Assume that adults have IQ scores that are normally distributed with a mean of 102.6 and a standard deviation of 21.2. Find the probability that a randomly selected adult has an IQ

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Question 1155356: Assume that adults have IQ scores that are normally distributed with a mean of 102.6 and a standard deviation of 21.2. Find the probability that a randomly selected adult has an IQ greater than 133.7. ​
Found 2 solutions by VFBundy, dkppathak:
Answer by VFBundy(438) About Me  (Show Source):
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z-score = %28x+-+mean%29%2FSD = %28133.7-102.6%29%2F21.2 = 31.1%2F21.2 = 1.47

Look up 1.47 on a z-table. The result is 0.9292. This is the probability that someone's IQ is LESS than 133.7. That means the probability that someone's IQ is GREATER than 133.7 is 0.0708.

Answer by dkppathak(439) About Me  (Show Source):
You can put this solution on YOUR website!
Assume that adults have IQ scores that are normally distributed with a mean of 102.6 and a standard deviation of 21.2. Find the probability that a randomly selected adult has an IQ greater than 133.7. ​
z=x-mue/sd
z=133.7-102.6/21.2
z=31.1/21.2=1.466
0.9286
greater than 133.7
probability 1-09286=0.0714
answer probability will be 0.0714