SOLUTION: A regular hexagon has consecutive vertices at (0,8) and (0,4). What is the exact area of the hexagon? What are the possible coordinates of the center?

Algebra ->  Surface-area -> SOLUTION: A regular hexagon has consecutive vertices at (0,8) and (0,4). What is the exact area of the hexagon? What are the possible coordinates of the center?      Log On


   



Question 1155309: A regular hexagon has consecutive vertices at (0,8) and (0,4). What is the exact area of the hexagon? What are the possible coordinates of the center?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

area:
A=%283sqrt%283%29%2F2%29a%5E2
a is equal to distance between two consecutive vertices
given:consecutive vertices at (0,8) and (0,4)
since x coordinate equal to zero, distance between y=8 andy=+4 is
a=4 units
A=%283sqrt%283%29%2F2%294%5E2
A=%283sqrt%283%29%2F2%2916
A=3sqrt%283%29%2A8
A=24sqrt%283%29+-> exact area
What are the possible coordinates of the center?

hexaon.png
since the triangle formed by each side and the lines joining the end points of the side to the circumcentre are equilateral,+r=a
r=4
if center is at (x,y)
y coordinate of the center is midpoint consecutive vertices at (0,8) and (0,4)
y=%288%2B4%29%2F2=6
calculate b using the right triangle with one side being 6-4=2 units and hypotenuse r=4
b%5E2=4%5E2-2%5E2
b%5E2=16-4
b%5E2=12
b=sqrt%2812%29
b=sqrt%284%2A3%29
b=2sqrt%283%29
so, the possible coordinates of the center are:
C(2sqrt%283%29,6) or C(-2sqrt%283%29,6)