SOLUTION: Can you please help me solve these problems. 1. Find an equation of the line containing the point (-2,5) with slope -3;slope-intercept form. 2. Find an equation of the line conta

Algebra ->  Graphs -> SOLUTION: Can you please help me solve these problems. 1. Find an equation of the line containing the point (-2,5) with slope -3;slope-intercept form. 2. Find an equation of the line conta      Log On


   

Question 1155218: Can you please help me solve these problems.
1. Find an equation of the line containing the point (-2,5) with slope -3;slope-intercept form.
2. Find an equation of the line containing the point (9,3) with slope -1/3; standard form.
Find an equation of the line containing the (-2,-3) with slope 1/8; slope-intercept form.
4. Find an equation of the line containing the point (4,0) with slope -3/16; standard form.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form for linear equations in two variables is ax%2Bby=c, and
slope-intercept form is y=mx%2Bb
1. Find an equation of the line containing the point (-2,5) with slope m=-3;slope-intercept form.
y=mx%2Bb.......plug in a slope and given x and y coordinates of the point
5=-3%28-2%29%2Bb
5=6%2Bb
b=5-6
b=-1
your equation is:
y=-3x-1


2. Find an equation of the line containing the point (9,3) with slope m=-1%2F3; standard form.
since given slope, start with slope intercept form
3=-%281%2F3%299%2Bb
3=-3%2Bb
b=3%2B3
b=6
y=-%281%2F3%29x%2B6
write in standard form:
ax%2Bby=c
%281%2F3%29x%2By=6 ...both sides multiply by 3
+x%2B3y=18

3. Find an equation of the line containing the (-2,-3) with slope m=1%2F8; slope-intercept form.
-3=%281%2F8%29%28-2%29%2Bb
-3=-%281%2F4%29%2Bb
%281%2F4%29-3=b
%281%2F4%29-12%2F4=b
-11%2F4=b
equation is:
y=%281%2F8%29x-11%2F4

4. Find an equation of the line containing the point (4,0) with slope -3%2F16; standard form.
since given slope, start with slope intercept form
0=-%283%2F16%294%2Bb
0=-%283%2Fcross%2816%294%29cross%284%29%2Bb
0=-%283%2F4%29%2Bb
%283%2F4%29=b
standard form of equation is:
y=-%283%2F16%29x%2B3%2F4.......both sides multiply by 16
16y=-3x%2B16%2A3%2F4
3x%2B16y=4%2A3
3x%2B16y=12