SOLUTION: Use the midpoint formula method to find the equation of the perpendicular bisector of the line segment whose endpoints are (-2,3) and (-8, 1) . Write the equation in double interce

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Use the midpoint formula method to find the equation of the perpendicular bisector of the line segment whose endpoints are (-2,3) and (-8, 1) . Write the equation in double interce      Log On


   

Question 1155216: Use the midpoint formula method to find the equation of the perpendicular bisector of the line segment whose endpoints are (-2,3) and (-8, 1) . Write the equation in double intercept form please thanks!
Found 3 solutions by ewatrrr, Alan3354, MathLover1:
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi  

(-2,3) and (-8, 1)

Midpoint Pt(x,y):  ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)

Midpoint: P(-5, 2)

m =%28y%5B1%5D+-+y%5B2%5D%29%2F%28x%5B1%5D+-+x%5B2%5D+%29

m =2/6 = 1/3

***Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29

y-2 = -3(x+5) 

y-2 = -3x -15

y = -3x -13

double intercept form

x/(-13/3) + y/-13 = 1

Wish You the Best in your Studies.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Use the midpoint formula method to find the equation of the perpendicular bisector of the line segment whose endpoints are (-2,3) and (-8, 1) . Write the equation in double intercept form
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Step 1, find the midpoint.
Step 2, find the slope of the line thru the points.
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The slope (call it m) of lines perpendicular is the negative inverse of the slope of the line thru the points.
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Then use y-y1 = m*(x-x1) where (x1,y1) is the mid-point.
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Ooooooh, you were "that close" to learning something, but another tutor did it for you.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the perpendicular bisector of the line segment whose endpoints are
(-2,3) and (-8, 1) will pass through mid-point (x,y)
(%28-2-8%29%2F2,%283%2B1%29%2F2)=>
(-5,2)
now find equation of the line which contain given endpoints
first calculate a slope:
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%281-3%29%2F%28-8-%28-2%29%29
m=+-2%2F%28-8%2B2%29
m=+-2%2F-6
m=+1%2F3

y=mx%2Bb...plug in a slope and coordinates of one point
3=%281%2F3%29%28-2%29%2Bb....solve for b
3=%28-2%2F3%29%2Bb
3%2B2%2F3=b
b=11%2F3

y=%281%2F3%29x%2B11%2F3=> the slope is 1%2F3

now find the perpendicular line:
recall: perpendicular line has a slope negative reciprocal to the slope of the line above
-1%2F%281%2F3%29=-3=>the slope of perpendicular line
y=-3x%2Bb.........use mid-point (-5,2) to calculate b
2=-3%28-5%29%2Bb
2=15%2Bb
b=2-15
b=-13
equation is: y=-3x-13