SOLUTION: Help please! Exact solutions: 8sin(3*theta) + 4sqrt(2)=0 on the interval [0,2pi).

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Question 1154935: Help please!
Exact solutions: 8sin(3*theta) + 4sqrt(2)=0 on the interval [0,2pi).
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Exact solutions:
8sin%283%2Atheta%29+%2B+4sqrt%282%29=0 on the interval [0,2pi).
8sin%283%2Atheta%29+=-4sqrt%282%29
sin%283%2Atheta%29+=-4sqrt%282%29%2F8
sin%283%2Atheta%29+=-sqrt%282%29%2F2

general solutions for sin%283theta%29=-+sqrt%282%29%2F2 is:
3theta=+5pi%2F4%2B2pi%2An
theta=+5pi%2F12%2B2pi%2An%2F3
3theta=7pi%2F4%2B2pi%2An
theta=7pi%2F12%2B2pi%2An%2F3

solutions for the range:0%3C=+theta+%3C2pi
theta=5pi%2F12
theta=7pi%2F12
theta=13pi%2F12
theta=5pi%2F4
theta=7pi%2F4
theta=23pi%2F12+