SOLUTION: Hi A cuboid measuring 25cm by 10cm by 6cm has two cones of 2cm radius each removed from it. What is the remaining surface area of the solid. Can you show me step by st

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Question 1154653: Hi
A cuboid measuring 25cm by 10cm by 6cm has two cones of 2cm radius each removed from it.
What is the remaining surface area of the solid.
Can you show me step by step how to calculate it.
Thanks
Found 2 solutions by ikleyn, mananth:
Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.

As it is worded, printed, posted and presented, the problem can not be solved and the question can not be answered,

since the height/(the heights) of the cones is/(are) not defined.



Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
.
I assume height of cone =6 cm
slant height of cone =sqrt( (6^2+2^2))= 6.32
When you remove the cones the area of base of cone will be removed and curved surface area will added to the cuboid
area of base of cone = pi * r^2 = 3.14*2^2=12.56 cm^2
2 bases so 2*12.56 = 25.12 cm^2
Curved surface area of cone = pi*r*l = 3.14*2*6.32= 39.68
2 cones 39.68*2 = 79.36 cm^2
Surface area of cuboid = 2(lw+wh+lh)
=2*(25*10+10*6+6*25)
=920 cm^2
Area remaining 920-25.12 +79.36
=974.24 cm^2
Check Calc