SOLUTION: Find real numbers​ a, b, and c so that the graph of the function y=ax^2+bx+c contains the points (-1,6),(3,7),(0,1)

Algebra ->  Matrices-and-determiminant -> SOLUTION: Find real numbers​ a, b, and c so that the graph of the function y=ax^2+bx+c contains the points (-1,6),(3,7),(0,1)      Log On


   

Question 1154621: Find real numbers​ a, b, and c so that the graph of the function y=ax^2+bx+c contains the points (-1,6),(3,7),(0,1)
Answer by greenestamps(13216) About Me  (Show Source):
You can put this solution on YOUR website!


Plug in the x and y values of the given points to get 3 equations in a, b, and c.

a-b%2Bc+=+6
9a%2B3b%2Bc+=+7
c+=+1

Use c=1 in the first two equations.

a-b+=+5
9a%2B3b+=+6

Eliminate b

3a-3b+=+15
9a%2B3b+=+6
12a+=+21
a+=+7%2F4

Solve for b

7%2F4-b+=+5
b+=+-13%2F4

ANSWER: (a,b,c) = (7/4,-13/4,1)