SOLUTION: i am a three digit number, my ten digit number is six times more than my ones, and my one hundred digit is eight less than the tens digit

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Question 1154526: i am a three digit number, my ten digit number is six times more than my ones, and my one hundred digit is eight less than the tens digit
Found 4 solutions by Edwin McCravy, Alan3354, MathLover1, josgarithmetic:
Answer by Edwin McCravy(20060) About Me  (Show Source):
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i am a three digit number, my ten digit number is six times more than my
ones,

That's impossible, because 6 is the only digit that can be 6 times a
digit, and it is 6 times 1.  So 6 has to be the tens digit.

But that means there cannot be a one hundred digit because no digit is 8
less than 6.

Who gave you an impossible problem?

Edwin

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
i am a three digit number, my ten digit number is six times more than my ones, and my one hundred digit is eight less than the tens digit
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"six times more" is not six more.
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Not possible, "six times more" = 7 times as much.
1 time more = 2x
2 times more = 3x
etc
============
The problem is gibberish.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
"my ten digit number is six times more than my ones" =>6 is the only digit that can be 6 times a digit, and it is 6%2A1=6.
So 6 has to be the tens digit.
then, "one hundred digit is 8 less than the tens digit" which is 6:=> no digit is 8less than 6

in case "six times more" was mistake and you have "six more" , than solution is possible


let units digit be x
since we have digits from 0 to 9, x is greater than or equal to 0 and less than or equal to+9
tens digit is 6 more than units digit:x%2B6
so
x%2B6%3C=9
x+%3C=9-6
x+%3C=3
hundreds digit is eight less than x%2B6:x%2B6-8=x-2
x-2%3E=0
x%3E=2

solutions:
x%3E=2 & x%3C=3-> take first whole number which is 2

therefore
if ones x=2+
tens x%2B6=8
hundreds x-2=0=> number is 082 which+is+not a three digit number
if x=3,
tens digit is 3%2B6=9 and
hundreds digit is 3%2B6-8=1
=> a three digit number is 193



Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
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my ten digit number is six times more than my ones, and my one hundred digit is eight less than the tens digit
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u, the ones digit
t, tens digit
h, hundreds digit

system%28t=u%2B6u%2Ch=-8%2Bt%29

system%28t=7u%2Ch=t-8%29

h=7u-8------------------Could u be 0, or 1, or 2, or 3?
u        h
0        -8
1        -7
2        6
3        13

The only possible value for the ones digit is 2; and therefore hundreds digit is 6. This still does not work, giving an unacceptable value for t.

Possible mistakes in the work (or in the problem's description.).