.
The given exponential equation
    
 + 
 = 
             (1)
is equivalent to
    
 + 
 = 
,   or
    
 + 
 = 
.          (2) 
Introduce new variables  u = 2^x,  v = 3^x.  Then equation (2) takes the form
    u^2 + u*v = 
.
Divide both sides by u^2.  You will get
    
 - 
 - 1 = 0                (3)
Let z = 
.   Then equation (3) takes the form
    z^2 - z - 1 = 0.
Solve this quadratic equation using the quadratic formula
    
 = 
 = 
.
The roots are  
    
 = 
,   and
    
 = 
.
Thus, we should consider two cases.
(a)  
 = 
.
     It means  
 = 
 = 
.
     Next, take any logarithm, log base 10, or natural logarithm "ln"  from both sides to continue
       
 = 
,
        x = 
 / 
 =  = 1.1868  (approximately).
    Thus this case is completed.
(b)  
 = - 
     It means  - 
 = 
 = 
.
     
     The left side is negative, while the right side is positive.
     So, this case has no solutions.
     
ANSWER.  The original equation has only one root  x = 
 / 
 =  = 1.1868  (approximately).
Solved.