Question 1154379: solution to sin^2x+3sinx+2=0 on [0,pi]
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39623)   (Show Source):
Answer by ikleyn(52834)  (Show Source):
You can put this solution on YOUR website! .
The given equation is equivalent to
(sin(x)+1)*(sin(x)+2) = 0
sin(x) + 2 NEVER can be equal to zero; THEREFORE, the only possibility is
sin(x) + 1 = 0, or, which is the same, sin(x) = -1 with the solution x =  ,
which is outside of the given interval.
ANSWER. In the given interval, the given equation HAS NO solution/solutions.
Answered, solved, explained and completed.
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