SOLUTION: If someone could please help me with this problem that would be great. Working alone Shana can rake the leaves in the yard in 4-1/2 hrs, while it takes John only 3 hrs to do the

Algebra ->  Rate-of-work-word-problems -> SOLUTION: If someone could please help me with this problem that would be great. Working alone Shana can rake the leaves in the yard in 4-1/2 hrs, while it takes John only 3 hrs to do the      Log On


   



Question 115432This question is from textbook
: If someone could please help me with this problem that would be great.
Working alone Shana can rake the leaves in the yard in 4-1/2 hrs, while it takes John only 3 hrs to do the same task. How fast can they rake the leaves if they work together if they both work at their original rates?
This question is from textbook

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Working alone Shana can rake the leaves in the yard in 4-1/2 hrs, while it takes John only 3 hrs to do the same task. How fast can they rake the leaves if they work together if they both work at their original rates?
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Let x = time required to complete the job when they work together
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Let the completed job = 1
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A simple equation
x%2F4.5 + x%2F3 = 1
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We can get rid of the denominators by multiplying by 9
9*x%2F4.5 + 9*x%2F3 = 9(1)
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Cancel out the denominators and you have:
2x + 3x = 9
:
5x = 9
:
x = 9%2F5
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x = 1.8 hrs working together:
:
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Check solution using the original equation:
1.8%2F4.5 + 1.8%2F3 =
.4 + .6 = 1