SOLUTION: write a two-column proof.
Given: AB ≅ AC
Prove: m ⟨B > m ⟨D
It's a triangle and the A" is at the top of triangle and B" is at the bottom of the triangle on the left s
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-> SOLUTION: write a two-column proof.
Given: AB ≅ AC
Prove: m ⟨B > m ⟨D
It's a triangle and the A" is at the top of triangle and B" is at the bottom of the triangle on the left s
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Question 1154135: write a two-column proof.
Given: AB ≅ AC
Prove: m ⟨B > m ⟨D
It's a triangle and the A" is at the top of triangle and B" is at the bottom of the triangle on the left side of the edge and C" is at the bottom of the triangle in the middle D" is also at the bottom of the triangle on the right side of the edge the triangle has a middle line going from A" downwards to C" the triangle is also leaning towards the left side little bit
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In triangle ABC AB congruent to AC ( given)
therefore angle ABC = angle ACB ( isosceles triangle)
in triangle ACD, angle ACB is exterior angle.
Therefore angle ACB is greater than interior angle D ( Exterior angle theorem)
But angle ABC = angle ACB .Therefore angle ABC greater than angle ADC
angle B > angle D
