SOLUTION: Can someone help me solve this problem asap?
1. Find the horizonal and vertical asymptotes of the following. Type "none" if the function does not have an asymptote.
A.f(x)=2x-3/x
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-> SOLUTION: Can someone help me solve this problem asap?
1. Find the horizonal and vertical asymptotes of the following. Type "none" if the function does not have an asymptote.
A.f(x)=2x-3/x
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Question 115406: Can someone help me solve this problem asap?
1. Find the horizonal and vertical asymptotes of the following. Type "none" if the function does not have an asymptote.
A.f(x)=2x-3/x^2+2
answer____________
Horizonal________
Vertical:____________
B. g(x)= 5x/x-1
Answer__________
Horizonal:________
Vertical_______
Thank you dearly Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website! By definition, is a straight line continually approaching but never meeting a curve, or a line whose distance to a given curve tends to zero. An asymptote may or may not intersect its associated curve.
1.
The asymptotes come from the zeroes of the denominator, so we need to set the denominator equal to and solve.
=+-
This has . Since the denominator has no zeroes, then and the domain is "all x".
Since the degree is greater in the denominator than in the numerator, the will be dragged down to the, and is therefore "". Since I have found a horizontal asymptote, I don't have to look for a slant asymptote. Then the full answer is:
domain: all
vertical asymptotes:
horizontal asymptote: (the )
slant asymptote:
2.
The is at .
set the denominator and set it equal to :
=>
a for this is...
--> ... --> -->... -->
