SOLUTION: Factor problems 9 - 12 by using the difference of squares method. 9. x^2 - 4 AThis polynomial cannot be factored by using the difference of squares method. B(x - 2)(

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor problems 9 - 12 by using the difference of squares method. 9. x^2 - 4 AThis polynomial cannot be factored by using the difference of squares method. B(x - 2)(      Log On


   



Question 1154000: Factor problems 9 - 12 by using the difference of squares method.

9. x^2 - 4
AThis polynomial cannot be factored by using the difference of squares method.
B(x - 2)(x - 2)
C(x - 2)(x - 1)
D(x - 2)(x + 2)
E (x - 1)(x - 4)
F (x + 2)(x + 2)


10. x^2 - 25
A(-x - 5)(x - 5)
BThis polynomial cannot be factored by using the difference of squares method.
C(-x + 5)(x + 5)
D(x - 5)(x + 5)
E (x + 5)(-x - 5)
F (x - 5)(x - 5)


11. 36x^4 - 4x^2
A(6x^2 - 2x)(6x^2 - 2x) = 4x^2(3x - 1)(3x - 1)
B(6x^2 + 2x)(6x^2 + 2x) = 2x^2(3x + 1)(2x + 1)
CThis polynomial cannot be factored by using the difference of squares method.
D(-6x^2 - 2x)(-6x^2 - 2x) = 4x^2(-3x - 1)(-3x - 1)
E (6x^2 - 2x)(6x^2 + 2x) = 4x^2(3x - 1)(3x + 1)
F (-6x^2 + 2x)(6x^2 - 2x) = 2x^2(-3x + 1)(3x - 1)


12. x^2 + 100
A(x + 10)(x - 10)
B(-x + 10)(x - 10)
C(x + 10)(x + 10)
DThis polynomial cannot be factored by using the difference of squares method.
E (x - 10)(x - 10)
F (-x + 10)(-x - 10)

Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
You are supposed to apply this fact:
%28x-a%29%28x%2Ba%29=x%5E2-a%5E2