SOLUTION: 10% of customers who walk into a golf store purchase a golf club and 30% of customers purchase golf balls. 6% of customers purchase both clubs and balls. the % of customers who do

Algebra ->  Probability-and-statistics -> SOLUTION: 10% of customers who walk into a golf store purchase a golf club and 30% of customers purchase golf balls. 6% of customers purchase both clubs and balls. the % of customers who do       Log On


   

Question 1153907: 10% of customers who walk into a golf store purchase a golf club and 30% of customers purchase golf balls. 6% of customers purchase both clubs and balls. the % of customers who do not purchase clubs or balls is?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The percentage that purchase either a golf club or golf balls or both is (10+30)-6 = 34.

(Count the customers who buy a golf club and add the number who buy golf balls; then subtract the number who buy both, because you have counted them twice.)

So the percentage who buy neither is 100-34 = 66.

ANSWER: 66% buy neither golf clubs nor golf balls

Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

The percentage of those who bought something (at least one of the two) is


    10% + 30% - 6% = 34%.


The percentage of those who bought nothing is the complement to it, i.e.


    100% - 34% = 66%.      ANSWER