.
From the condition, the roots of the quadratic function are x= 2 and x= 5.
Therefore, the quadratic form in factored form is
y(x) = a*(x-2)*(x-5),
where "a" is an arbitrary (now unknown) real number.
To find the value of "a", use the condition y(1) = 8, which leads to the equation
a*(1-2)*(1-5) = 8, or
a*(-1)*(-4) = 8,
4a = 8,
a =
= 2.
The final factorized form of the given quadratic function is
y(x) = 2*(x-1)*(x-5).
Solved.