Question 1153512: Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of those who took the MCAT at WSSU, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 6.5. Suppose that (unknown to you) the mean score of those taking the MCAT at WSSU is 25.0. If you sample 25 students, what is mean of the sampling distribution of x-bar?
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The sampling distribution of the mean is a normal distribution with mean 25 and standard deviation 6.5/sqrt(25), or 1.3
N~(25, 1.3)
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