Question 1153455: NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+217t+185.
Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
The rocket splashes down after ________ seconds.
How high above sea-level does the rocket get at its peak?
The rocket peaks at __________ meters above sea-level.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source):
Answer by ikleyn(52902)  (Show Source):
You can put this solution on YOUR website! .
In my post, I only want to explain to the visitor, that the given equation DOES NOT describe the flight of a real rocket.
It describe the flight of a PROJECTILE, i.e. an object launched with the initial velocity of 217 m/s,
but then falling freely under the Earth's gravitation force.
The drag force, which provides vertical acceleration of a real rocket, ABSENTS in the given equation (!)
So, it is not a real rocket (!) (!)
Such object has a common name "a projectile" in Physics.
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