SOLUTION: If a number is added to the numerator of 7 8 and twice as much is added to the denominator, the result is 8 13 . Find the number.
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-> SOLUTION: If a number is added to the numerator of 7 8 and twice as much is added to the denominator, the result is 8 13 . Find the number.
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Question 1153397
:
If a number is added to the numerator of
7
8
and twice as much is added to the denominator, the result is
8
13
.
Find the number.
Found 2 solutions by
jim_thompson5910, mananth
:
Answer by
jim_thompson5910(35256)
(
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):
You can
put this solution on YOUR website!
x = number added to old numerator
old numerator = 7
new numerator = 7+x
old denominator = 8
new denominator = 8+2x, since twice as much is added here
old fraction =
new fraction =
new fraction =
(given info)
Set
equal to
. Solve for x.
-------------------------
Cross multiply
Distribute
Separate out common or like terms.
Combine like terms
Divide both sides by 3
This is the answer.
-------------------------
Using that x value, we can see that,
new numerator = 7+x = 7+9 = 16
new denominator = 8+2x = 8+2*9 = 26
new fraction =
The answer is confirmed.
-------------------------
Answer:
9
Answer by
mananth(16946)
(
Show Source
):
You can
put this solution on YOUR website!
let x be the number added to the numerator
13(7+x)=8(8+2x)
91+13x=64+16x
3x=27
x=9