SOLUTION: How long does it take for an investment to double in value if it is invested at 4​% compounded quarterly question mark  Compounded​ continuously?

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Question 1153381: How long does it take for an investment to double in value if it is invested at 4​% compounded quarterly question mark  Compounded​ continuously?
Found 2 solutions by math_helper, ikleyn:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

+F+=+P%281+%2B+r%2Fn%29%5E%28nt%29++ (1)
where
F = future value
P = present value
r = annual interest rate
n = number of payments per year
t = number of years

This problem asks to find t for F=2P, r=4% (0.04), and n=4 interest payments per year:
+2P+=+P%281+%2B+0.04%2F4%29%5E%284t%29+
Cancel P from both sides, and simplify where possible:
+2+=+%281.01%29%5E%284t%29+
Take ln() of both sides:
+ln%282%29+=+4t%2Aln%281.01%29+
Solve for t:
+t+=+ln%282%29%2F%284%2Aln%281.01%29%29+=+0.69315%2F0.03980+=+17.415+ years
+highlight%28+t+=+17.415+%29+ years (about 17yrs, 151.6days}

--------------
For continuous compounding:
+F+=+Pe%5E%28rt%29+ (2)
[ ----------------------
An aside: formula (2) can be derived by taking the limit of (1) as n goes to infinity:
++F+=+P%281%2Br%2Fn%29%5E%28nt%29+
Replace r/n by 1/(n/r) and raise the inner expression first to the 'n/r'
power, and then to the 'rt' power (so the r's would cancel if we carried
it out):
++F+=+P%28green%281%2B%281%2F%28n%2Fr%29%29%5E%28n%2Fr%29%29%29%5E%28rt%29+
The green expression has a limit of 'e' as n-->infinity:
+F+=+Pe%5E%28rt%29+
--------------------- ]
+2P+=+Pe%5E%280.04t%29+
+2+=+e%5E%280.04t%29+
+ln%282%29+=+0.04t+
+highlight%28+t+=+17.329+%29+ years (about 17yrs, 120days)


Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.

For the quarterly compounding, the answer MUST BE ROUNDED to the closest larger integer number of quarters (!)

It gives the correct answer 17 and half of a year (17.5 years) in this case.